- Implement Queue using Stacks
Implement a first in first out (FIFO) queue using only two stacks. The implemented queue should support all the functions of a normal queue (push
, peek
, pop
, and empty
).
Implement the MyQueue
class:* void push(int x)
Pushes element x to the back of the queue.* int pop()
Removes the element from the front of the queue and returns it.* int peek()
Returns the element at the front of the queue.* boolean empty()
Returns true
if the queue is empty, false
otherwise.
Notes:* You must use only standard operations of a stack, which means only push to top
, peek/pop from top
, size
, and is empty
operations are valid.* Depending on your language, the stack may not be supported natively. You may simulate a stack using a list or deque (double-ended queue) as long as you use only a stack’s standard operations.
Example 1:
**Input**
["MyQueue", "push", "push", "peek", "pop", "empty"]
[[], [1], [2], [], [], []]
**Output**
[null, null, null, 1, 1, false]
**Explanation**
MyQueue myQueue = new MyQueue();
myQueue.push(1); // queue is: [1]
myQueue.push(2); // queue is: [1, 2] (leftmost is front of the queue)
myQueue.peek(); // return 1
myQueue.pop(); // return 1, queue is [2]
myQueue.empty(); // return false
Constraints:* 1 <= x <= 9
* At most 100
calls will be made to push
, pop
, peek
, and empty
.* All the calls to pop
and peek
are valid.
Follow-up: Can you implement the queue such that each operation is amortized O(1)
time complexity? In other words, performing n
operations will take overall O(n)
time even if one of those operations may take longer.
JavaScript Solution
var MyQueue = function() {
this.inputStack = []
this.outputStack = []
};
/**
* @param {number} x
* @return {void}
*/
MyQueue.prototype.push = function(x) {
this.inputStack.push(x)
};
/**
* @return {number}
*/
MyQueue.prototype.pop = function() {
if(!this.outputStack.length){
while(this.inputStack.length){
this.outputStack.push(this.inputStack.pop())
}
}
if(!this.outputStack.length){
return null
}
return this.outputStack.pop()
};
/**
* @return {number}
*/
MyQueue.prototype.peek = function() {
if(!this.outputStack.length){
while(this.inputStack.length){
this.outputStack.push(this.inputStack.pop())
}
}
if(!this.outputStack.length){
return null
}
return this.outputStack[this.outputStack.length-1]
};
/**
* @return {boolean}
*/
MyQueue.prototype.empty = function() {
return !this.inputStack.length && !this.outputStack.length
};
/**
* Your MyQueue object will be instantiated and called as such:
* var obj = new MyQueue()
* obj.push(x)
* var param_2 = obj.pop()
* var param_3 = obj.peek()
* var param_4 = obj.empty()
*/
标签:return,0232,FIFO,queue,MyQueue,pop,outputStack,push,FILO
From: https://blog.csdn.net/avenccssddnn/article/details/140162081