给定一个未排序的整数数组 nums ,找出数字连续的最长序列(不要求序列元素在原数组中连续)的长度。
请你设计并实现时间复杂度为 O(n) 的算法解决此问题。
示例 1:
输入:nums = [100,4,200,1,3,2]
输出:4
解释:最长数字连续序列是 [1, 2, 3, 4]。它的长度为 4。
示例 2:
输入:nums = [0,3,7,2,5,8,4,6,0,1]
输出:9
提示:
0 <= nums.length <= 105
-109 <= nums[i] <= 109
class Solution:
def longestConsecutive(self, nums: List[int]) -> int:
n = len(nums)
d = set(nums)
nlongestCons = 0
for num in nums:
if num-1 in d:
pass
else:
thisN = 1
while(num+1 in d):
thisN +=1
num+=1
if thisN>nlongestCons:
nlongestCons = thisN
return nlongestCons
标签:最长,nums,nlongestCons,thisN,序列,num,128,leetCode
From: https://www.cnblogs.com/lulululuyan/p/18180308