Build a 4-bit shift register (right shift), with asynchronous reset, synchronous load, and enable.
areset: Resets shift register to zero.
load: Loads shift register with data[3:0] instead of shifting.
ena: Shift right (q[3] becomes zero, q[0] is shifted out and disappears).
q: The contents of the shift register.
If both the load and ena inputs are asserted (1), the load input has higher priority.
1 module top_module(
2 input clk,
3 input areset, // async active-high reset to zero
4 input load,
5 input ena,
6 input [3:0] data,
7 output reg [3:0] q);
8 always @(posedge clk or posedge areset)begin
9 if(areset)begin //在最高位次首先实现reset=1时的复位
10 q <= 4'b0;
11 end
12 else if(load) begin //如果load=1,则进行加载
13 q <= data;
14 end
15 else if(ena)begin //实现右移的功能,这个{1'b0,q[3:1]}写得巧妙
16 q <= {1'b0,q[3:1]};
17 end
18 else begin
19 q <= q;
20 end
21 end
22
23 endmodule
再写:
上面写的代码仿真的时候没有出错,但是应该是没有完成题目中If both the load and ena inputs are asserted (1), the load input has higher priority.
的要求,修改如下:
module top_module(
input clk,
input areset, // async active-high reset to zero
input load,
input ena,
input [3:0] data,
output reg [3:0] q);
always@(posedge clk,posedge areset)begin
if(areset)begin
q<=4'b0;
end
else begin
case({load,ena})
2'b10:begin
q<=data;
end
2'b01:begin
q<={1'b0,q[3:1]};
end
2'b11:begin
q<=data;
end
3'b00:begin
q<=q;
end
endcase
end
end
endmodule
标签:load,ena,shift,register,areset,input,bit
From: https://www.cnblogs.com/jzzg/p/18129268