Implement a generic RequiredByKeys<T, K>
which takes two type argument T
and K
.
K
specify the set of properties of T
that should set to be required. When K
is not provided, it should make all properties required just like the normal Required<T>
.
For example
interface User {
name?: string
age?: number
address?: string
}
type UserRequiredName = RequiredByKeys<User, 'name'> // { name: string; age?: number; address?: string }
/* _____________ Your Code Here _____________ */
export type MergeObject<T> = { [P in keyof T]: T[P] };
type RequiredByKeys<T, K extends keyof T = keyof T> = MergeObject<
Omit<T, K> & {
[Key in keyof T as Key extends K ? Key: never]-?: T[Key]
}
>
/* _____________ Test Cases _____________ */
import type { Equal, Expect } from '@type-challenges/utils'
interface User {
name?: string
age?: number
address?: string
}
interface UserRequiredName {
name: string
age?: number
address?: string
}
interface UserRequiredNameAndAge {
name: string
age: number
address?: string
}
type cases = [
Expect<Equal<RequiredByKeys<User, 'name'>, UserRequiredName>>,
Expect<Equal<RequiredByKeys<User, 'name' | 'age'>, UserRequiredNameAndAge>>,
Expect<Equal<RequiredByKeys<User>, Required<User>>>,
// @ts-expect-error
Expect<Equal<RequiredByKeys<User, 'name' | 'unknown'>, UserRequiredName>>,
]
标签:Typescript,string,RequiredByKeys,number,50,address,type,name From: https://www.cnblogs.com/Answer1215/p/16792739.html