现象：systemctl start httpd 启动超时，提示信息如下：
Job for httpd.service failed because the control process exited with error code. See "systemctl status httpd.service" and "journalctl -xe" for details.
systemctl status httpd信息如下：
httpd.service: start operation timed out. Terminating. httpd.service: Failed with result 'timeout'.
相关日志中没有报错，如/var/log/httpd/error_log、/var/log/message；且当使用systemctl 启动或重启时，ctrl+c 中断命令，然后使用systemctl status httpd 或ps查看进程时，httpd进程正常运行。
网上搜索到的解决方法：
1. 加长服务启动超时时间（未解决）
# vim /usr/lib/systemd/system/httpd.service.d/timeout.conf [Service] TimeoutStartSec=600 # systemctl daemon-reload # sysetmctl show httpd # journalctl -u httpd # systemctl restart httpd
参考链接：
https://askubuntu.com/questions/1309084/how-do-i-avoid-timeouts-and-get-apache2-to-start-at-system-startup#
2.修改service启动命令（未解决）
# /usr/lib/systemd/system/httpd.service ExecStart=/usr/sbin/httpd $OPTIONS -DFOREGROUND 改为 ExecStart=/bin/bash -c "/usr/sbin/httpd $OPTIONS -DFOREGROUND"
3.修改service环境变量（未解决）
# /usr/lib/systemd/system/httpd.service Environment=LANG=C 改为 Environment=APACHE_STARTED_BY_SYSTEMD=true
参考链接：
https://askubuntu.com/questions/1309084/how-do-i-avoid-timeouts-and-get-apache2-to-start-at-system-startup#
4.注释service Type（解决）
# /usr/lib/systemd/system/httpd.service 将下述内容注释 Type=notify
# systemctl dameon-reload
原因：notify需加载mod_systemd 模块
新建文件用以加载所需模块 # vim /etc/httpd/conf.modules.d/systemc.conf LoadModule systemd_module modules/mod_systemd.so 将service Type注释取消
# systemctl daemon-reload
# systemctl restart httpd
参考链接：
https://www.mankier.com/8/httpd.service#Description-Automated_service_restarts
资料截图：
标签：httpd,systemd,service,system,systemctl,usr,超时 From： https://www.cnblogs.com/sswind/p/18054151