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Go 100 mistakes - #61: Propagating an inappropriate context

时间：2024-02-23 10:56:43浏览次数：34

标签：inappropriate 61 mistakes context 100 Propagating

疑问：

前两种情况（1. 客户端连接中断 2. HTTP请求取消）发生，publish却不expire也不会被cancel，这样会不会有问题？

标签：inappropriate,61,mistakes,context,100,Propagating
From： https://www.cnblogs.com/zhangzhihui/p/18029004

POJ--1961 Period(KMP)
记录18:262024-2-22http://poj.org/problem?id=1961利用KMP构造next数组，其实next数组就是方便于找到下一个应该比较的字符，或者说是不动目标字符，移动查找字符，这里面利用next数组就可以很快捷的移动这道题是利用next字符，给出证明的结果是当i-next[i]能整除i时，S[1~i-......
6361
6361.【NOIP2019模拟2019.9.18】鲳数(pair)题目大意求l到r的逆序对和题解首先规定\(num_{up}[i]\)表示从高位到低位（n~i）组成的数，\(num_{low}[i]\)从低位到高位（1~i）组成的数，a[i]表示第i位的数值1~n是低位到高位举个栗子：12345中\(num_{up}[3]=345,num_{low}[4]=1234\)考虑一......
洛谷 P6610 [Code+#7] 同余方程
题目描述给出若干组正整数\(p\)和\(x\)，求方程\(a^2+b^2\equivx\pmodp\)关于\(a\)和\(b\)在模\(p\)意义下解的组数，其中\(p\)是奇数，且不包含平方因子题解来整一个更注重于观察结构而不是计算的题解（首先使用CRT将问题转化为模奇质数的结果相乘是显然的......
Go 100 mistakes - #50: Checking an error type inaccurately
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Go 100 mistakes - #45: Returning a nil receiver
We’veseeninthissectionthatinGo,havinganilreceiverisallowed,andaninterfaceconvertedfromanilpointerisn’tanilinterface.Forthatreason,whenwehave toreturnaninterface,weshouldreturnnotanilpointerbuta......
Go 100 mistakes - #42: Not knowing which type of receiver to use
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Go 100 mistakes - #41: Substrings and memory leaks
WeneedtokeeptwothingsinmindwhileusingthesubstringoperationinGo. First,theintervalprovidedisbasedonthenumberofbytes,notthenumberofrunes. Second,asubstringoperationmayleadtoamemoryleakastheresultings......
Go 100 mistakes - #39: Under-optimized string concatenation
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Go 100 mistakes - #37: Inaccurate string iteration
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Go 100 mistakes - #35: Using defer inside a loop
Wewillimplementafunctionthatopensasetoffileswherethefilepathsare receivedviaachannel.Hence,wehavetoiterateoverthischannel,openthefiles,and handletheclosure.Here’sourfirstversion:Thereisasignificantproblemwithth......

Go 100 mistakes - #61: Propagating an inappropriate context

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