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ajax 前后端交互

时间:2022-10-12 21:00:17浏览次数:61  
标签:old 前后 request back dic ajax new password 交互

前端

<script>
    $('#id_edit').click(function () {
        $.ajax({
            url:'/set_password/',
            type:'post',
            data:{
                'old_password':$('#id_old_password').val(),
                'new_password':$('#id_new_password').val(),
                'confirm_password':$('#id_confirm_password').val(),
                'csrfmiddlewaretoken':'{{ csrf_token }}',

            },
            success:function(args){
                if (args.code==1000){
                   // window.location.href='/login/'
                    window.location.reload()
                }else{
                    $('#id_password_error').text(args.msg)
                }

            }
        })


    })

  后端

@login_required
def set_password(request):


    # if request.method=='POST':
    if request.is_ajax():
        back_dic = {'code':1000,'msg':''}
        if request.method=='POST':


            old_password = request.POST.get('old_password')
            new_password = request.POST.get('new_password')
            confirm_password = request.POST.get('confirm_password')

            #校验原密码是否正确
            is_right = request.user.check_password(old_password)
            if is_right:
                if new_password == confirm_password:
                    request.user.set_password(new_password)  # 如果密码相同则设置密码并保存
                    request.user.save()
                    back_dic['msg'] = '修改成功'
                else:
                    back_dic['code'] = 1001
                    back_dic['msg'] = '两次密码不一致'
            else:
                back_dic['code']= 1002
                back_dic['msg'] = '原密码错误'

    return JsonResponse(back_dic)

  

 

标签:old,前后,request,back,dic,ajax,new,password,交互
From: https://www.cnblogs.com/shclbear/p/16785953.html

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