task4 code
1 #include<stdio.h> 2 3 int main() { 4 FILE* fp; 5 long cnt = 0, c = 0; 6 char ch; 7 8 fp = fopen("data4.txt", "r"); 9 if (fp == NULL) { 10 printf("failed to open"); 11 return 1; 12 } 13 14 fseek(fp, 0L, SEEK_END); 15 cnt = ftell(fp); 16 fseek(fp, 0L, SEEK_SET); 17 18 while (1) { 19 ch = fgetc(fp); 20 if (ch == '\n' || ch == ' ') 21 c++; 22 if (ch == EOF) 23 break; 24 } 25 cnt--; 26 printf("data4.txt中共包含字符数(除去空白):%ld", cnt - c); 27 fclose(fp); 28 29 return 0; 30 }View Code
task5 code
1 #include <stdio.h> 2 #include <string.h> 3 #include <stdlib.h> 4 #define N 10 5 6 typedef struct { 7 long int id; 8 char name[20]; 9 float objective; // 客观题得分 10 float subjective; // 操作题得分 11 float sum; // 总分 12 char ans[10]; // 考试结果 13 } STU; 14 15 void finput(STU st[], int n); 16 void foutput(STU st[], int n); 17 void output(STU st[], int n); 18 int process(STU st[], int n, STU st_pass[]); 19 20 int main() { 21 STU stu[N], stu_pass[N]; 22 int cnt; 23 double pass_rate; 24 25 printf("从文件读入%d个考生信息...\n", N); 26 finput(stu, N); 27 28 printf("\n对考生成绩进行统计...\n"); 29 cnt = process(stu, N, stu_pass); 30 31 printf("\n通过考试的名单:\n"); 32 output(stu, N); // 输出到屏幕 33 foutput(stu, N); // 输出到文件 34 35 pass_rate = 1.0 * cnt / N; 36 printf("\n本次等级考试通过率: %.2f%%\n", pass_rate * 100); 37 38 return 0; 39 } 40 // 把通过考试的考生完整信息输出到屏幕上 41 // 准考证号,姓名,客观题得分,操作题得分,总分,结果 42 void output(STU st[], int n) { 43 int i; 44 45 printf("准考证号\t姓名\t客观题得分\t操作题得分\t总分\t\t结果\n"); 46 for (i = 0; i < n; i++) 47 printf("%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t\t%s\n", st[i].id, 48 st[i].name, st[i].objective, st[i].subjective, st[i].sum, st[i].ans); 49 } 50 // 从文本文件examinee.txt读入考生信息:准考证号,姓名,客观题得分,操作题得分 51 void finput(STU st[], int n) { 52 int i; 53 FILE* fin; 54 55 fin = fopen("examinee.txt", "r"); 56 if (fin == NULL) { 57 printf("fail to open file\n"); 58 exit(0); 59 } 60 61 while (!feof(fin)) { 62 for (i = 0; i < n; i++) 63 fscanf(fin, "%ld %s %f %f", &st[i].id, st[i].name, 64 &st[i].objective, &st[i].subjective); 65 } 66 67 fclose(fin); 68 } 69 // 把通过考试的考生完整信息写入文件list_pass.txt 70 // 准考证号,姓名,客观题得分,操作题得分,总分,结果 71 void foutput(STU s[], int n) { 72 FILE* fout; 73 int i; 74 75 // 保存到文件 76 fout = fopen("list_pass.txt", "w"); 77 if (!fout) { 78 printf("fail to open or create list_pass.txt\n"); 79 exit(0); 80 } 81 82 fprintf(fout, "准考证号\t\t姓名\t客观题得分\t操作题得分\t总分\t\t结果\n"); 83 84 for (i = 0; i < n; i++) 85 fprintf(fout, "%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t\t%s\n", s[i].id, 86 s[i].name, s[i].objective, s[i].subjective, s[i].sum, s[i].ans); 87 88 fclose(fout); 89 } 90 // 对考生信息进行处理:计算每位考生考试总分、结果;统计考试通过的人数 91 int process(STU st[], int n, STU st_pass[]) { 92 int i, j = 0; 93 94 for (i = 0; i < n; i++) { 95 st[i].sum = st[i].objective + st[i].subjective; 96 if (st[i].sum >= 60) { 97 strcpy(st[i].ans, "pass"); 98 st_pass[j++] = st[i]; 99 } 100 else 101 strcpy(st[i].ans, "fail"); 102 } 103 104 return j; 105 }View Code
task5 result
task6 code
1 #include<stdio.h> 2 #include<stdlib.h> 3 #include<time.h> 4 #define M 0 5 #define N 79 6 7 typedef struct { 8 long int id; 9 char name[20]; 10 char class[40]; 11 }STU; 12 13 void foutput(int ran[], STU stu[]); 14 15 int main() { 16 FILE* fp; 17 STU stu[100]; 18 int ran[5]; 19 int i = 0, j = 0, k = 0; 20 21 srand((unsigned int)time(NULL)); 22 for (i = 0; i < 5; i++) { 23 ran[i] = rand() % (N - M + 1) + M; 24 } 25 26 fp = fopen("list.txt", "r"); 27 if (fp == NULL) { 28 printf("failed to open"); 29 return 1; 30 } 31 i = 0; 32 while (!feof(fp)) { 33 fscanf(fp, "%ld %s %s", &stu[i].id, &stu[i].name, &stu[i].class); 34 i++; 35 } 36 i--; 37 for (j = 0; j < 5; j++, k++) 38 printf("%ld %s %s\n", stu[ran[k]].id, stu[ran[k]].name, stu[ran[k]].class); 39 foutput(ran, stu); 40 fclose(fp); 41 42 return 0; 43 } 44 45 void foutput(int ran[], STU stu[]) { 46 FILE* fout; 47 int i, k = 0; 48 49 fout = fopen("lucky.txt", "w"); 50 if (!fout) { 51 printf("fail to open or create list_pass.txt\n"); 52 exit(0); 53 } 54 55 for (i = 0; i < 5; i++,k++) 56 fprintf(fout, "%ld %s %s\n",stu[ran[k]].id, stu[ran[k]].name, stu[ran[k]].class); 57 58 fclose(fout); 59 }View Code
task6 result
标签:fp,STU,int,st,stu,实验,pass From: https://www.cnblogs.com/nuist0415/p/17901880.html