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稀疏数组

时间:2023-12-14 14:11:41浏览次数:31  
标签:11 数组 int array1 稀疏 ints out

https://blog.csdn.net/baolingye/article/details/99943083

package com.chen.Two;

/**
 * @author Chen
 * @date 2023年12月14日 11:05
 */
public class SparseArray {
    public static void main(String[] args) {
        int[][] array1 = new int[11][11]; //起始数组
        array1[1][2] = 1;
        array1[2][3] = 2;
        for (int[] ints : array1) {
            for (int anInt : ints) {
                System.out.print(anInt+"\t");
            }
            System.out.println();
        }
        int sum = 0; //计算数组中的有效数
        for (int i = 0; i < array1.length; i++) {
            for (int j = 0; j <array1.length; j++) {
                if (array1[i][j]!=0){
                    sum++;
                }
            }
        }
        System.out.println("有效个数为:"+sum);
        int[][] array2 = new int[sum+1][3]; //稀疏数组
        array2[0][0] = array1.length;
        array2[0][1] = array1.length;
        array2[0][2] = sum;
        for (int i = 0; i < array1.length; i++) {
            for (int j = 0; j < array1.length; j++) {
                if (array1[i][j]!=0){
                    array2[i][0] = i;
                    array2[i][1] = j;
                    array2[i][2] = array1[i][j];
                }
            }
        }
        for (int i = 0; i < array2.length; i++) {
            for (int j = 0; j < array2.length; j++) {
                System.out.print(array2[i][j]+"\t");
            }
            System.out.println();
        }
        //还原稀疏数组
        int[][] array3 = new int[array2[0][0]][array2[0][1]];
        for (int i = 1; i < array2.length; i++) {
            array3[array2[i][0]][array2[i][1]] = array2[i][2];
        }
        for (int[] ints : array3) {
            for (int anInt : ints) {
                System.out.print(anInt+"\t");
            }
            System.out.println();
        }
    }
}

标签:11,数组,int,array1,稀疏,ints,out
From: https://www.cnblogs.com/qwer12138/p/17901057.html

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