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COMP 340 操作系统 Bounded Buffer问题解决

时间:2023-11-22 19:46:33浏览次数:31  
标签:10 product Buffer COMP materials will program Bounded tools

这里有3个发生器,每个发生器独立地产生一种独特的材料。所有这些材料在被转发给操作员之前被存储在大小为10的输入缓冲器中。 我们有三个具有相同优先级的运营商,他们负责生产基于这些材料。每种产品需要2种不同的材料。每次操作员需要2个用于此目的的工具。总共为这些操作员提供了3种工具。操作员只能一次处理一个产品。当操作员同时获得材料和工具时,他可以在0.01秒至1秒的有限时间内生产产品。否则,他会 等到所有的必需品都得到满足。他可以先拿材料或工具,没关系,但他一次只能得到一件事。如果操作员决定在他开始制作当前的产品,他可以把材料和工具放回去,然后重新获得新的材料和工具。但他必须在完成一个产品后将工具放回原处,因为其他操作员可能需要这些工具。所有产品都被放入一个大小不受限制的输出队列中。一 操作员在将产品放入输出队列之前不能启动新产品。一些限制可能适用于这些产品:1)在这个过程中,任何相同的产品都不能相邻队列我们说,如果两种产品是由相同的材料制成的,它们是相同的。2)生产的任何两种产品的数量之差应小于10例如,我们可以有10个产品A和15个产品B,但如果我们有10个A和B的21,因为差值是大于10的11。


COMP 340 – Operating Systems
Fall, 2023
HW2: Bounded Buffer Problem
PROBLEM STATEMENT:
There are 3 generators and each produces a unique kind of material independently. All these
materials are stored in an input buffer with size 10 before they are forwarded to the operators.
We have 3 operators with same priority who are responsible for producing the products based on
these materials. Each product needs 2 different kinds of materials. Each time an operator needs 2
tools for this purpose. There are totally 3 tools provided for these operators. An operator can only
process one product at one time. When an operator gets both the materials and tools, he can
produce a product within a limited time varied from 0.01 second to 1 second. Otherwise, he has
to wait until all the necessities are met. He can grab the materials or tools first, it does not matter,
but he can only get one thing at one time. If an operator decides to make another product before
he starts to make the current product, he can put the materials and tools back and re-get the new
materials and tools. But he has to put the tools back after he finishes a product because other
operators may need these tools. All the products are put into a size-unlimited output queue. An
operator cannot start a new product before he puts the product into the output queue. Some
restrictions may apply to these products: 1) No same products can be next to each other in this
queue. We say that two products are same if they are made from the same kinds of materials. 2)
The difference of the number of any two kinds of products produced should be less than 10, for
example, we can have 10 of product A and 15 of product B, but it is not allowed if we have 10 of
A and 21 of B because the difference is 11 which is larger than 10.
SUBMISSION INSTRUCTIONS
Your assignments must be both emailed and presented in class on the due date. You will submit
a single .ZIP, .RAR or .TAR file that will contain:
1) A soft copy of your source code.
2) A Makefile to compile the code.
3) A soft copy of a report documenting the internal design of your program.
Your program must be in C/C++. It is your responsibility to make sure your program compiles
and runs smoothly under Linux. Your program should not be stalled in a dead cycle at any time.
This is the only submission method
.
DEADLINE
The deadline for homework is 11:59:59 PM on Wednesday, December 1
st, 2023. Submissions
after this deadline will be considered late and will NOT be accepted. Do not present code in a
PDF or Word document – it must be an executable .c file as in the case of the midterm. Email a
zip file to [email protected] . Do not upload to Blackboard.
GRADING
Your homework assignment is worth 10 points (10%). During the execution of your program,
you should provide these information dynamically:
1) For each material, how many of them are generated?
2) The status of the input buffer.
3) For each kind of product, how many are produced?
4) The status of the output queue.
5) How many times the deadlock happens?
Additional Notes:
Students need to be careful to design their solution in a way that avoids any potential deadlocks
that could be caused by these scenarios:
• A glut of materials of the same type in the materials queue (solution: students should
incorporate some mechanism to guarantee that there is sufficient variety in the materials
queue)
• Workers hogging tools (Possible solutions: workers attempt to grab PAIRS of tools
instead of picking them up individually. Alternatively, when a worker is holding on to a
single tool, there needs to be some mechanism like a counter that keeps track of attempts
to grab the second tool. After a certain number of unsuccessful attempts, the worker
should release the tool its holding, which would allow some other thread to grab it.)
Also provide these functions
1) Pause and resume the program at any time. 2) Make the number of operators and tools
adjustable.
Please feel free to provide additional information and functions that you consider useful.
The most important thing is to make sure your program works correctly. Do not worry about
your programming style or efficiency. But it does matter if you provide a smarter internal design
(approach) and user-friendly interface.
IMPORTANT: Your program must COMPILE AND RUN or you will get a mark of ZERO on
your assignment.
Assignment grades will be open for review for one week only.
Finally, a reminder that plagiarism will result in an automatic failing grade for the course.

 

标签:10,product,Buffer,COMP,materials,will,program,Bounded,tools
From: https://www.cnblogs.com/whenjava/p/17850125.html

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