链表逆置
public class Solution {
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param head ListNode类
* @return ListNode类
*/
public ListNode ReverseList (ListNode head) {
// write code here
ListNode pre = null;
ListNode cur = head;
while(cur!=null){
ListNode next= cur.next;
cur.next = pre;
pre = cur;
cur = next;
}
return pre;
}
}
链表有环
https://www.cnblogs.com/chenyi502/p/17494929.html
标签:pre,head,ListNode,cur,next,链表 From: https://www.cnblogs.com/chenyi502/p/17849635.html