flask 文件上传与接收

在做flask后端，有个需求是将视频从前端上传至后端，然后再页面播放上传的视频，记录下知识点。

文件流接收

1、前端传来的对象是二进制文件流，有两种方法保存本地。

（1）通过open()方法将文件流写入保存

（2）直接用调用 file.save() 方法保存传来的文件流：

from flask import Flask,request
app = Flask(__name__)


@app.route('/upload',methods = ['POST'])
def file_receive():
    # 获取文件对象
    file = request.files['file']
    # 获取文件名
    filename = file.filename
    # file.save 也可保存传来的文件
    # file.save(f'./{filename}')
    with open(f'./{filename}','wb') as f:
        f.write(file.stream.read())

    return {'success':1}

if __name__ == '__main__':
    app.run()

测试该段代码的文件上传可以用requests实现，用open()创建一个二进制对象，传给后端：

import requests

def uploads():
    url = 'http://127.0.0.1:5000/upload'
    files = {'file':open('C:\\Users\\xxx\\Desktop\\push\\test.mp4','rb')}
    r = requests.post(url,files = files)
    print(r.text)

if __name__=="__main__":
    uploads()

2、如果既要传参数又要传文件呢，用 request.data 可以获取前端传来的参数：

from flask import Flask,request
app = Flask(__name__)

@app.route('/upload',methods = ['POST'])
def file_receive():
    # 获取文件对象
    file = request.files['file']
    # 获取参数body
    body = request.data
    filename = file.filename
    # file.save 也可保存传来的文件
    # file.save(f'./{filename}')
    with open(f'./{filename}','wb') as f:
        f.write(file.stream.read())

    return {'success':1}

if __name__ == '__main__':
    app.run()

 requests 测试代码：

import requests

def uploads():
    url = 'http://127.0.0.1:5000/upload'
    body = {'info':'test'}
    files = {'file':open('C:\\Users\\xxx\\Desktop\\push\\test.mp4','rb')}
    r = requests.post(url,json = body,files = files)
    print(r.text)

if __name__=="__main__":
    uploads()