import java.util.Stack; public abstract class AbstractCommand { public abstract int execute(int value); public abstract int undo(); public abstract int redo(); } public class AddCommand extends AbstractCommand { private Adder adder = new Adder(); private Stack<Integer> unStack = new Stack<Integer>();// 返回栈,用来记录所做的每一步操作,用于撤回 private Stack<Integer> reStack = new Stack<Integer>();// 重复栈,用来存储返回栈弹出的数据,由于重复 /** * 撤回 * */ public int undo() { int i=0; if (unStack.isEmpty()) { i=-1; }else{ Integer pop = unStack.pop(); reStack.push(pop); if(!unStack.isEmpty()){//判断弹出数据后是否为空,如果为空,说明已撤回到最原始状态 i=unStack.peek(); } } return i; } /** * 恢复 */ public int redo() { int i=0; if (reStack.isEmpty()) { i=-1; }else{//撤回时只要可以可以撤回,则返回栈一定有数据 Integer pop = reStack.pop(); unStack.push(pop); i=pop; } return i; } /** * 执行计算,并进行栈的更新 */ public int execute(int value) { int v = 0; if (unStack.isEmpty()) {// 说明还没有数据 v = adder.add(value); unStack.push(v); } else {// 需要更新两个栈中的内容,并计算结果,其中返回栈应该更新,重复栈应该清空 v = adder.add(value); unStack.push(v); if (!reStack.isEmpty()) { for (int i = 0; i < reStack.size(); i++) { reStack.pop(); } } } return v; } } public class Adder { private int num =0; public int add(int value) { num+=value; return num; } } public class CalculatorForm { private AbstractCommand command; public void setCommand(AbstractCommand command) { this.command =command; } /** * 执行运算 * @param value */ public void compute(int value) { command.execute(value); } /** * 撤回 */ public void undo() { int i = command.undo(); if(i==-1){ System.out.println("缓存中已不存在数据"); }else{ System.out.println("执行成功,运算结果是:"+i); } } /** * 恢复 */ public void redo() { int i = command.redo(); if(i==-1){ System.out.println("已恢复至最新数据"); } else{ System.out.println("执行成功,运算结果是:"+i); } } } public class Client { public static void main(String[] args) { CalculatorForm form = new CalculatorForm(); AddCommand command = new AddCommand(); form.setCommand(command); //计算 System.out.println("------计算过程------"); form.compute(1); form.compute(2); form.compute(3); form.compute(4); //多次撤回 System.out.println("------撤回过程------"); form.undo(); form.undo(); form.undo(); form.undo(); form.undo(); //多次恢复 System.out.println("------恢复过程------"); form.redo(); form.redo(); form.redo(); form.redo(); form.redo(); } }
标签:总结,23.11,form,19,undo,unStack,int,redo,public From: https://www.cnblogs.com/laobing6214/p/17843184.html