- 图dp
class Solution {
public int uniquePaths(int m, int n) {
int dp[][] = new int[m][n];
for(int i = 0; i < m; i++){
for(int j = 0; j < n; j++){
if(i == 0 && j == 0) dp[i][j] = 1;
else if(i == 0) dp[i][j] = dp[i][j-1];
else if(j == 0) dp[i][j] = dp[i-1][j];
else dp[i][j] = dp[i-1][j] + dp[i][j-1];
}
}
return dp[m-1][n-1];
}
}
标签:leetcode62,int,不同,路径,else,++,dp
From: https://www.cnblogs.com/xzh-yyds/p/16599418.html