题目
Given a binary tree, find its maximum depth.
The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
Note: A leaf is a node with no children.
Example:
Given binary tree [3,9,20,null,null,15,7],
3
/ \
9 20
/ \
15 7
return its depth = 3.
题目大意
要求输出一棵树的最大高度。
解题思路
这一题递归遍历就可,遍历根节点的左孩子的高度和根节点右孩子的高度,取出两者的最大值再加一即为总高度。
参考代码
package leetcode
import (
"github.com/halfrost/LeetCode-Go/structures"
)
// TreeNode define
type TreeNode = structures.TreeNode
/**
* Definition for a binary tree node.
* type TreeNode struct {
* Val int
* Left *TreeNode
* Right *TreeNode
* }
*/
func maxDepth(root *TreeNode) int {
if root == nil {
return 0
}
return max(maxDepth(root.Left), maxDepth(root.Right)) + 1
}
func max(a int, b int) int {
if a > b {
return a
}
return b
}
标签:node,Binary,TreeNode,int,Tree,Maximum,maxDepth,return,root
From: https://blog.51cto.com/u_16110811/8285846