移除链表元素
题意:删除链表中等于给定值 val 的所有节点。
示例 1: 输入:head = [1,2,6,3,4,5,6], val = 6 输出:[1,2,3,4,5]
示例 2: 输入:head = [], val = 1 输出:[]
示例 3: 输入:head = [7,7,7,7], val = 7 输出:[]
实现代码如下:(本代码是通过带头节点的单链表来实现的)
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode() {}
* ListNode(int val) { this.val = val; }
* ListNode(int val, ListNode next) { this.val = val; this.next = next; }
* }
*/
/**
定义一个带头节点的单链表
*/
class Solution {
public ListNode removeElements(ListNode head, int val) {
if (head == null) {
return head;
}
ListNode dummy = new ListNode(-1, head);
ListNode pre = dummy;//待删除节点的前一个节点
ListNode cur = head;//cur是当前待删除节点
while (cur != null) {
if (cur.val == val) {
pre.next = cur.next;
} else {
pre = cur;
}
cur = cur.next; //cur指针向后移动
}
return dummy.next;
}
}
标签:head,01,ListNode,cur,val,next,链表,移除
From: https://www.cnblogs.com/codingbao/p/17783652.html