无脑

检查是否存在满足条件的数字组合

import java.util.Scanner;
import java.util.*;


// 注意类名必须为 Main, 不要有任何 package xxx 信息
public class Main {
    public static void main(String[] args) {
         Scanner in = new Scanner(System.in);
        int count = Integer.parseInt(in.nextLine());
        String[] split = in.nextLine().split(" ");
        int[] arr = new int[count];
        for (int i = 0; i < count; i++) {
            arr[i] = Integer.parseInt(split[i]);
        }

        Arrays.sort(arr);
        reverse(arr);

        for (int i = 0; i < arr.length; i++) {
            int A = arr[i];
            for (int j = i + 1; j < arr.length; j++) {
                int B = arr[j];
                for (int k = j + 1; k < arr.length; k++) {
                    int C = arr[k];
                    if (A == B + 2 * C){
                        System.out.println(A + " " + B + " " + C);
                        return;
                    }
                    if (A == C + 2 * B){
                        System.out.println(A + " " + C + " " + B);
                        return;
                    }
                }
            }
        }
        System.out.println(0);
    }
    public static void reverse(int[] arr){
        int l = 0;
        int r = arr.length - 1;
        while (l < r){
            int temp = arr[l];
            arr[l] = arr[r];
            arr[r] = temp;
            l++;
            r--;
        }
    }
}