1132 Cut Integer（附测试点浮点错误）

题目：

Cutting an integer means to cut a K digits lone integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devided by the product of A and B, as 167334 / (167 × 334) = 3. Given an integer Z, you are supposed to test if it is such an integer.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (≤ 20). Then N lines follow, each gives an integer Z (10 ≤ Z <231). It is guaranteed that the number of digits of Z is an even number.

Output Specification:

For each case, print a single line Yes if it is such a number, or No if not.

Sample Input:

3
167334
2333
12345678

Sample Output:

Yes
No
No

易错：

c++运算符优先级 !的优先级比%大   https://blog.csdn.net/nicky_zs/article/details/4053146 

浮点错误：要注意除数为0的情况

代码：

#include<stdio.h>
#include<iostream>
using namespace std;
int main(){
    int n;
    scanf("%d", &n);
    for(int i = 0; i < n; i++){
        int z, t, num = 0;
        scanf("%d", &z);
        t = z; 
        while(t != 0){
            t /= 10;
            num++;
        }
        int w = 1;
        for(int j = 0; j < num / 2; j++){
            w *= 10;
        }
        int a = z / w;
        int b = z % w;
        int c = a * b;
        if(c != 0 && z % c == 0){
            printf("Yes\n");
        }else{
            printf("No\n");
        }
    }
    return 0;
}