判断大小端
使用强制类型转换
#include <stdio.h>
int main()
{
int num = 1;
char* ch = (char*)(&num);
if(*ch == 1)
printf("小端\n");
else
printf("大端\n");
return 0;
}
使用联合体
#include <stdio.h>
union um {
int i;
char q;
};
int main()
{
union um un;
un.i = 1;
if (un.q == 1)
printf("小端\n");
else
printf("大端\n");
return 0;
}
标签:小端,判断,int,char,un,printf,大小,main
From: https://blog.51cto.com/u_15562309/7335069