模拟实现一个简单的计算器

void menu()
{
	printf("**********************\n");
	printf("**** 1.Add  2.Sub ****\n");
	printf("**** 3.Mlu  4.Del ****\n");
	printf("*****    0.exit   ****\n");
	printf("**********************\n");
}
int Add(int x, int y)
{
	return x + y;
}
int Sub(int x, int y)
{
	return x - y;
}
int Mul(int x, int y)
{
	return x * y;                    
}
int Del(int x, int y)
{
	return x / y;
}
void calcu(int (*p)(int,int))
{
	int x = 0;
	int y = 0;
	int ret = 0;
	printf("请输入2个操作数：");
	scanf("%d %d", &x, &y);
	ret = p(x, y);
	printf("%d\n", ret);
}
int main()
{
	int i = 0;
	do
	{
		menu();
		printf("请输入:");
		scanf("%d", &i);
		switch (i)
		{
		case 0:
			printf("退出计算器\n");
			break;
		case 1:
			calcu(Add);
			break;
		case 2:
			calcu(Sub);
			break;
		case 3:
			calcu(Mul);
			break;
		case 4:
			calcu(Del);
			break;
		default:
			printf("输入错误，重新输入\n");
			break;
		}
	} while (i);
	return 0;
}