题目
Implement strStr().
Return the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack.
Example 1:
Input: haystack = "hello", needle = "ll"
Output: 2
Example 2:
Input: haystack = "aaaaa", needle = "bba"
Output: -1
Clarification:
What should we return when needle is an empty string? This is a great question to ask during an interview.
For the purpose of this problem, we will return 0 when needle is an empty string. This is consistent to C's strstr() and Java's indexOf().
题目大意
实现一个查找 substring 的函数。如果在母串中找到了子串,返回子串在母串中出现的下标,如果没有找到,返回 -1,如果子串是空串,则返回 0 。
解题思路
这一题比较简单,直接写即可。
参考代码
package leetcode
import "strings"
// 解法一
func strStr(haystack string, needle string) int {
for i := 0; ; i++ {
for j := 0; ; j++ {
if j == len(needle) {
return i
}
if i+j == len(haystack) {
return -1
}
if needle[j] != haystack[i+j] {
break
}
}
}
}
// 解法二
func strStr1(haystack string, needle string) int {
return strings.Index(haystack, needle)
}
标签:子串,strStr,string,needle,28,return,Implement,haystack
From: https://blog.51cto.com/u_16110811/7189164