The mook jong
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 326 Accepted Submission(s): 252
Problem Description
![](../../data/images/C613-1001-1.jpg)
ZJiaQ want to become a strong man, so he decided to play the mook jong。ZJiaQ want to put some mook jongs in his backyard. His backyard consist of n bricks that is 1*1,so it is 1*n。ZJiaQ want to put a mook jong in a brick. because of the hands of the mook jong, the distance of two mook jongs should be equal or more than 2 bricks. Now ZJiaQ want to know how many ways can ZJiaQ put mook jongs legally(at least one mook jong).
Input
There ar multiply cases. For each case, there is a single integer n( 1 < = n < = 60)
Output
Print the ways in a single line for each case.
Sample Input
1
2
3
4
5
6
Sample Output
1
2
3
5
8
12
#include <stdio.h>
__int64 a[61];
int main()
{
a[1]=1;
a[2]=2;
a[3]=3;
for(int i=4;i<61;i++)
{
a[i]=a[i-1]+a[i-3]+1;
}
int n;
while(~scanf("%d",&n))
{
printf("%I64d\n",a[n]);
}
return 0;
}