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ABC312

时间:2023-07-29 23:44:49浏览次数:41  
标签:ac return int rep ABC312 cin false

T1:Chord

模拟

代码实现
s = input()
if s in 'ACE, BDF, CEG, DFA, EGB, FAC, GBD':
    print('Yes')
else:
    print('No')

T2:TaK Code

模拟

代码实现
#include <bits/stdc++.h>
#define rep(i, n) for (int i = 0; i < (n); ++i)

using namespace std;

bool check(vector<string> s) {
    rep(i, 3)rep(j, 3) if (s[i][j] != '#') return false;
    rep(i, 3)rep(j, 3) if (s[8-i][8-j] != '#') return false;
    rep(i, 4)rep(j, 4) {
        if (i < 3 and j < 3) continue;
        if (s[i][j] != '.') return false;
        if (s[8-i][8-j] != '.') return false;
    }
    return true;
}

int main() {
    int n, m;
    cin >> n >> m;
    
    vector<string> s(n);
    rep(i, n) cin >> s[i];
    
    rep(si, n-8)rep(sj, m-8) {
        vector<string> t(9);
        rep(i, 9)rep(j, 9) t[i] += s[si+i][sj+j];
        if (check(t)) cout << si+1 << ' ' << sj+1 << '\n';
    }
    
    return 0;
}

T3:Invisible Hand

二分答案

代码实现
#include <bits/stdc++.h>
#define rep(i, n) for (int i = 0; i < (n); ++i)

using namespace std;

int main() {
    int n, m;
    cin >> n >> m;
    
    vector<int> a(n), b(m);
    rep(i, n) cin >> a[i];
    rep(i, m) cin >> b[i];
    
    int wa = 0, ac = 1001001001;
    while (ac-wa > 1) {
        int wj = (ac+wa)/2;
        int na = 0, nb = 0;
        rep(i, n) if (a[i] <= wj) na++;
        rep(i, m) if (b[i] >= wj) nb++;
        if (na >= nb) ac = wj; else wa = wj;
    }
    
    cout << ac << '\n';
    
    return 0;
}

标签:ac,return,int,rep,ABC312,cin,false
From: https://www.cnblogs.com/Melville/p/17590814.html

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