我的疑惑来源于源码中的函数式接口没有加@FunctionalInterface也可以支持lambda表达式
例如RedisTemplate的源码:
@Override public Boolean expire(K key, final long timeout, final TimeUnit unit) { byte[] rawKey = rawKey(key); long rawTimeout = TimeoutUtils.toMillis(timeout, unit); return execute(connection -> { try { return connection.pExpire(rawKey, rawTimeout); } catch (Exception e) { // Driver may not support pExpire or we may be running on Redis 2.4 return connection.expire(rawKey, TimeoutUtils.toSeconds(timeout, unit)); } }, true); }
execute的第一个参数使用了lambda表达式,而第一个参数却没有声明@FunctionalInterface:
@Nullable public <T> T execute(RedisCallback<T> action, boolean exposeConnection) { return execute(action, exposeConnection, false); }
/** * Callback interface for Redis 'low level' code. To be used with {@link RedisTemplate} execution methods, often as * anonymous classes within a method implementation. Usually, used for chaining several operations together ( * {@code get/set/trim etc...}. * * @author Costin Leau */ public interface RedisCallback<T> { /** * Gets called by {@link RedisTemplate} with an active Redis connection. Does not need to care about activating or * closing the connection or handling exceptions. * * @param connection active Redis connection * @return a result object or {@code null} if none * @throws DataAccessException */ @Nullable T doInRedis(RedisConnection connection) throws DataAccessException; }
bing搜索了一下:
标签:execute,return,rawKey,Redis,connection,FunctionalInterface,必须 From: https://www.cnblogs.com/gzhich2019/p/17580020.html