标签：String nums int posCnt 记负 num avg HJ97

1. 题目

读题

HJ97 记负均正

 

 

考查点

 

2. 解法

思路

 

代码逻辑

 

具体实现

 

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int n = Integer.valueOf(sc.nextLine());
        String[] nums = sc.nextLine().split("\\s+");
        count(nums);
    }

    public static void count(String[] nums) {

        int negCnt = 0;
        int posCnt = 0;
        double posSum = 0;
        for (int i = 0; i < nums.length; i++) {
            int num = Integer.valueOf(nums[i]);
            if (num < 0) {
                negCnt++;

            } else if (num > 0) {
                posCnt++;
                posSum += num;
            }
        }
        String avg;
        if (posCnt == 0) {
            avg = "0.0";
        } else {
            avg = new DecimalFormat("#0.0").format((double) posSum / posCnt);
        }

        System.out.print(negCnt + " " + avg);

    }
}

3. 总结

标签：String,nums,int,posCnt,记负,num,avg,HJ97
From： https://www.cnblogs.com/shoshana-kong/p/17542219.html