把两个数据结构相同的数组（数组下有n个对象）合并成一个数组

标签：... console 数组 下有 arr1 var 数据结构 log

数据拼接

有一个数组

let arr1 = [

{name:''lili",age:14},

{name:''小明",age:16},

{name:''张三",age:24},

]

let arr2 = [

{class:"初一二班",gender:"0"},

{class:"初一三班",gender:"1"},

{class:"初一五班",gender:"1"},

]

let newArr = []

this.newArr= this.arr1.map((item,index)=>{             return {...item, ...this.arr2[index]}   }) 最后输出的结果为 newArr=[

{name:''lili",age:14,class:"初一二班",gender:"0"},

{name:''小明",age:16,class:"初一三班",gender:"1"},

{name:''张三",age:24,class:"初一五班",gender:"1"},

]     若是数据结构单一的数组拼接（数组里面不嵌套对象）

ES6数组解构（...array）实现数组复制

vararr1=['a','b','c','d'];

vardd=[...arr1];

dd[]='es6';

console.log(dd);//["es6", "b", "c", "d"]

console.log(arr1);//["a", "b", "c", "d"]

数组concat方法，实现数组复制

var arr1=['a','b','c','d'];

var cc=arr1.concat();

cc[1]='yy';

console.log(arr1);//["a", "b", "c", "d"]

console.log(cc);//["a", "yy", "c", "d"]

通过es6数组解构实现数组合并

var arr1=['a','b','c','d'];

var arr2=['d'];

var arr3=['e','f'];

var dd=[...arr1,...arr2,...arr3];

console.log(dd);//["a", "b", "c", "d", "d", "e", "f"]

通过concat方法实现数组合并

var arr1=['a','b','c','d'];

var arr2=['d'];

var arr3=['e','f'];

var cc=arr1.concat(arr2,arr3);

console.log(cc);//["a", "b", "c", "d", "d", "e", "f"]

标签：...,console,数组,下有,arr1,var,数据结构,log
From： https://www.cnblogs.com/yangzhulian/p/16738474.html