def transform36(n):
res = []
while n:
res.append(n%36)
n = n//36
out = []
for rr in res[::-1]:
if 0 <= rr <= 9:
out.append(str(rr))
else:
out.append(chr(rr +ord('a')-10))
return ''.join(out)
# 简单测试一下
print(transform36(int(36 * 35))) # z0
标签：transform36,10,转换,进制,res,36 From： https://www.cnblogs.com/zle1992/p/17519722.html