思路:题目比较好懂的模拟题,用一个优先队列即可
模拟的时候要注意最后还会再开一次门,把剩下的人全部放进来,开门的时间并不一定是递增的,要自己排个序,还有就是要注意开门的时候是2 5这种数据,就是到第二个人到了开门,然后可以放5个人进来,这样不处理的话会RE
#include<bits/stdc++.h>
using namespace std;
const int maxn = 150000+7;
struct Node
{
char name[205];
int w;
int id;
bool operator < (const Node&a)const
{
if(w==a.w)
return id>a.id;
return w<a.w;
}
}p[maxn];
struct node
{
int t;
int peo;
}pp[maxn];
bool cmp(node a,node b)
{
return a.t<b.t;
}
int ans[maxn];
int main()
{
int T;
scanf("%d",&T);
while(T--)
{
memset(ans,0,sizeof(ans));
int n,m,q;
scanf("%d%d%d",&n,&m,&q);
for(int i = 1;i<=n;i++)
{
scanf("%s%d",p[i].name,&p[i].w);
p[i].id = i;
}
for(int i = 1;i<=m;i++)
scanf("%d%d",&pp[i].t,&pp[i].peo);
sort(pp+1,pp+1+m,cmp);
priority_queue<Node>que;
int cnt = 1;int res = 1;
for(int i = 1;i<=m;i++)
{
int tim = pp[i].t;
for(;cnt<=tim;cnt++)
que.push(p[cnt]);
int lim = pp[i].peo;
for(int j = 1;j<=lim&&!que.empty();j++)
{
Node tmp = que.top();que.pop();
ans[res++]=tmp.id;
}
}
for(;cnt<=n;cnt++)
que.push(p[cnt]);
while(!que.empty())
{
Node tmp = que.top();
que.pop();
ans[res++]=tmp.id;
}
for(int i = 1;i<q;i++)
{
int x;
scanf("%d",&x);
printf("%s ",p[ans[x]].name);
}
int x;scanf("%d",&x);
printf("%s\n",p[ans[x]].name);
}
}
Description
, and all of them will come at a different time. Because the lobby is not large enough, Alisha can only let a few people in at a time. She decides to let the person whose gift has the highest value enter first.
Each time when Alisha opens the door, she can decide to let
people enter her castle. If there are less than
people in the lobby, then all of them would enter. And after all of her friends has arrived, Alisha will open the door again and this time every friend who has not entered yet would enter.
If there are two friends who bring gifts of the same value, then the one who comes first should enter first. Given a query
Please tell Alisha who the
Input
, where
.
In each test case, the first line contains three numbers
and
separated by blanks.
is the number of her friends invited where
. The door would open m times before all Alisha’s friends arrive where
. Alisha will have
queries where
.
The
of the following
lines gives a string
, which consists of no more than
English characters, and an integer
,
, separated by a blank.
is the name of the
person coming to Alisha’s party and Bi brings a gift of value
.
Each of the following
lines contains two integers
and
separated by a blank. The door will open right after the
person arrives, and Alisha will let
friends enter her castle.
The last line of each test case will contain
numbers
separated by a space, which means Alisha wants to know who are the
friends to enter her castle.
Note: there will be at most two test cases containing
.
Output
For each test case, output the corresponding name of Alisha’s query, separated by a space.
Sample Input
15 2 3Sorey 3 Rose 3 Maltran 3 Lailah 5 Mikleo 6 1 1 4 2 1 2 3
Sample Output
Sorey Lailah Rose