如何在派生类调用基类的同名方法

需求

C++派生类希望覆盖基类同名方法，但不使用虚函数直接覆盖。

实现

通过namespace区别基类方法的调用。在线试验
https://godbolt.org/z/McKqaoP3r

#include <iostream>

class base
{
public:
    void show()
    {
        std::cout << "This is base speaking." << std::endl;
    }
};

class other: public base
{
public:
    void show()
    {
        base::show();
        std::cout << "This is other speaking." << std::endl;
    }
};

int main()
{
    other o;
    o.show();
    return 0;
}

结果

ASM generation compiler returned: 0
Execution build compiler returned: 0
Program returned: 0
This is base speaking.
This is other speaking.