/*
一: 字符串反转
1 code
2 原理图
*/
一: 字符串反转
1 code
def traverse(s):
print(s)
if len(s) == 0:
return s
return traverse(s[1:]) + s[0]
if __name__ == '__main__':
s = "abcd"
s1 = traverse(s)
print(s1)
2 原理图
标签：__,traverse,code,return,递归,s1,原理图 From： https://www.cnblogs.com/huafan/p/17363210.html