Instructions
Create a function that takes an integer as an argument and returns "Even" for even numbers or "Odd" for odd numbers.
Solution
def even_or_odd(number):
return 'Odd' if number % 2 else 'Even'
标签:Even,even,number,numbers,EvenOrOdd,odd
From: https://www.cnblogs.com/artwalker/p/17353254.html