最佳存款方案

         1.定义两个双精度浮点数a,b = 1000;

         2.循环5次从后往前计算存款数；

          3.循环内 a = b/(1 + 12 * 0.0063)

              b = a + 1000;

#include<iostream>
using namespace std;
int main()
{
double a, b = 1000;
for (int i = 1; i <= 5; i++) {
a = b / (1 + 12 * 0.0063);
b = a + 1000;
}
cout << a;
return 0;
}