运算符重载

一、加号重载运算符

- 实现两个自定义数据进行相加

class Person {
public:
    Person() {};
    Person(int a, int b)
    {
        this->m_A = a;
        this->m_B = b;
    }
    //成员函数实现 + 号运算符重载
    Person operator+(const Person& p) {
        Person temp;
        temp.m_A = this->m_A + p.m_A;
        temp.m_B = this->m_B + p.m_B;
        return temp;
    }


public:
    int m_A;
    int m_B;
};

//全局函数实现 + 号运算符重载
//Person operator+(const Person& p1, const Person& p2) {
//    Person temp(0, 0);
//    temp.m_A = p1.m_A + p2.m_A;
//    temp.m_B = p1.m_B + p2.m_B;
//    return temp;
//}

//运算符重载 可以发生函数重载 
Person operator+(const Person& p2, int val)  
{
    Person temp;
    temp.m_A = p2.m_A + val;
    temp.m_B = p2.m_B + val;
    return temp;
}

void test() {

    Person p1(10, 10);
    Person p2(20, 20);

    //成员函数方式
    Person p3 = p2 + p1;  //相当于 p2.operaor+(p1)
    cout << "mA:" << p3.m_A << " mB:" << p3.m_B << endl;


    Person p4 = p3 + 10; //相当于 operator+(p3,10)
    cout << "mA:" << p4.m_A << " mB:" << p4.m_B << endl;

}

int main() {

    test();

    system("pause");

    return 0;
}

二、左移运算符重载

class Person {
    friend ostream& operator<<(ostream& out, Person& p);

public:

    Person(int a, int b)
    {
        this->m_A = a;
        this->m_B = b;
    }

    //成员函数 实现不了  p << cout 不是我们想要的效果
    //void operator<<(Person& p){
    //}

private:
    int m_A;
    int m_B;
};

//全局函数实现左移重载
//ostream对象只能有一个
ostream& operator<<(ostream& out, Person& p) {
    out << "a:" << p.m_A << " b:" << p.m_B;
    return out;
}

void test() {

    Person p1(10, 20);

    cout << p1 << "hello world" << endl; //链式编程
}

int main() {

    test();

    system("pause");

    return 0;
}

三、递增运算符重载

class MyInteger {

    friend ostream& operator<<(ostream& out, MyInteger myint);

public:
    MyInteger() {
        m_Num = 0;
    }
    //前置++
    MyInteger& operator++() {
        //先++
        m_Num++;
        //再返回
        return *this;
    }

    //后置++
    MyInteger operator++(int) {
        //先返回
        MyInteger temp = *this; //记录当前本身的值，然后让本身的值加1，但是返回的是以前的值，达到先返回后++；
        m_Num++;
        return temp;
    }

private:
    int m_Num;
};


ostream& operator<<(ostream& out, MyInteger myint) {
    out << myint.m_Num;
    return out;
}


//前置++ 先++ 再返回
void test01() {
    MyInteger myInt;
    cout << ++myInt << endl;
    cout << myInt << endl;
}

//后置++ 先返回 再++
void test02() {

    MyInteger myInt;
    cout << myInt++ << endl;
    cout << myInt << endl;
}

int main() {

    test01();
    //test02();

    system("pause");

    return 0;
}

在递增重载运算符当中，需要注意前置递增和后置递增的区别

前置递增：MyInteger& operator++()

后置递增： MyInteger operator++(int)

而且目前不是很懂后置递增中，参数为什么是int？