题目
中文
实现一个通用的RequiredByKeys<T, K>
,它接收两个类型参数T
和K
。
K
指定应设为必选的T
的属性集。当没有提供K
时,它就和普通的Required<T>
一样使所有的属性成为必选的。
例如:
interface User {
name?: string;
age?: number;
address?: string;
}
type UserRequiredName = RequiredByKeys<User, 'name'>; // { name: string; age?: number; address?: string }
English
Implement a generic RequiredByKeys<T, K>
which takes two type argument T
and K
.
K
specify the set of properties of T
that should set to be required. When K
is not provided, it should make all properties required just like the normal Required<T>
.
For example
interface User {
name?: string;
age?: number;
address?: string;
}
type UserRequiredName = RequiredByKeys<User, 'name'>; // { name: string; age?: number; address?: string }
答案
type RequiredByKeys<
T extends object,
K extends keyof T | string = keyof T,
H = {
[P in K extends keyof T ? K : never]: Exclude<T[P], null | undefined>;
} & { [P in Exclude<keyof T, K>]?: T[P] }
> = { [P in keyof H]: H[P] };
标签:Typescript,string,RequiredByKeys,number,PartialRequired,体操,address,type,name
From: https://www.cnblogs.com/laggage/p/type-challenge-required-by-keys.html