超过经理收入的员工
select e1.name as Employee from Employee e1, Employee e2 where e1.managerId = e2.id and e1.salary > e2.salary
select e1.name as Employee from Employee e1 left join Employee e2 on e1.managerId = e2.id where e1.salary > e2.salary
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标签:salary,where,managerId,181,Employee,e1,leetcode,e2 From: https://www.cnblogs.com/carlzhang19/p/17306357.html