滑动窗口-leetcode344-反转字符出啊

编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 s 的形式给出。

不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。

示例 1：

输入：s = ["h","e","l","l","o"]
输出：["o","l","l","e","h"]
示例 2：

输入：s = ["H","a","n","n","a","h"]
输出：["h","a","n","n","a","H"]
提示：

1 <= s.length <= 105
s[i] 都是 ASCII 码表中的可打印字符
Related Topics

思路-滑动窗口

//leetcode submit region begin(Prohibit modification and deletion)
class Solution {
    public void reverseString(char[] s) {
        int left = 0;
        int right = s.length-1;
        while(left < right){
            char temp = s[left];
            s[left] = s[right];
            s[right] = temp;
            left++;
            right--;
        }

    }
}
//leetcode submit region end(Prohibit modification and deletion)