编写一个函数,其作用是将输入的字符串反转过来。输入字符串以字符数组 s 的形式给出。
不要给另外的数组分配额外的空间,你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。
示例 1:
输入:s = ["h","e","l","l","o"]
输出:["o","l","l","e","h"]
示例 2:
输入:s = ["H","a","n","n","a","h"]
输出:["h","a","n","n","a","H"]
提示:
1 <= s.length <= 105
s[i] 都是 ASCII 码表中的可打印字符
Related Topics
思路-滑动窗口
//leetcode submit region begin(Prohibit modification and deletion)
class Solution {
public void reverseString(char[] s) {
int left = 0;
int right = s.length-1;
while(left < right){
char temp = s[left];
s[left] = s[right];
s[right] = temp;
left++;
right--;
}
}
}
//leetcode submit region end(Prohibit modification and deletion)
标签:字符,right,leetcode344,数组,滑动,输入,left
From: https://www.cnblogs.com/xiaoshahai/p/17285809.html