题目描述:
编写一个函数,其作用是将输入的字符串反转过来。输入字符串以字符数组 s 的形式给出。
不要给另外的数组分配额外的空间,你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。
示例 1:
输入:s = ["h","e","l","l","o"]
输出:["o","l","l","e","h"]
示例 2:
输入:s = ["H","a","n","n","a","h"]
输出:["h","a","n","n","a","H"]
提示:
1 <= s.length <= 105
s[i]
都是 ASCII 码表中的可打印字符
思路:
定义两个指针(也可以说是索引下标),一个从字符串前面,一个从字符串后面,两个指针同时向中间移动,并交换元素。
以字符串hello
为例,过程如下:
class Solution{ public void reverseString(char s[]){ int l=0; int r = s.length-1; while(l<r){ char temp = s[l]; s[l] = s[r]; s[r] = temp; l++;r--; } } }
标签:示例,int,反转,LeetCode344,数组,字符串,输入 From: https://www.cnblogs.com/zhz123567/p/17246546.html