abcde->bcdea

 1 package com.itheima.test;
 2 
 3 public class Test2Case1 {
 4     public static void main(String[] args) {
 5         /*给定两个字符串
 6         A 旋转，将A最左边字符移动至最右边
 7         abcde->bcdea
 8         若干次调整，A变成B，返回True*/
 9         //定义两个字符串
10         String str1 = "abcde";
11         String str2 = "chb";
12         //旋转
13         String rotate = rotate(str1);
14         System.out.println(rotate);
15         boolean check = check(str1, str2);
16         System.out.println(check);
17     }
18 
19     public static boolean check(String strA,String strB){
20         for (int i = 0; i < strA.length(); i++) {
21             strA = rotate(strA);   //关键步骤
22             if(strA.equals(strB)){
23                 return true;
24             }
25         }
26         return false;
27     }
28     //subString截取
29     //旋转字符串类型，返回值还是字符串
30     public static String rotate(String str){
31         //获取第一个字符
32         char first = str.charAt(0);
33         //截取掉第一个，后面全部变成字符串
34         String end = str.substring(1);
35         return end+first;
36     }
37 }

 1 package com.itheima.test;
 2 
 3 public class Test2Case2 {
 4     public static void main(String[] args) {
 5         /*给定两个字符串
 6         A 旋转，将A最左边字符移动至最右边
 7         abcde->bcdea
 8         若干次调整，A变成B，返回True*/
 9         //定义两个字符串
10         String str1 = "abcde";
11         String str2 = "chb";
12         //旋转
13         //String rotate = rotate(str1);
14         //System.out.println(rotate);
15         boolean result = check(str1, str2);
16         System.out.println(result);
17     }
18 
19     public static boolean check(String strA,String strB){
20         for (int i = 0; i < strA.length(); i++) {
21             strA = rotate(strA);   //关键步骤
22             if(strA.equals(strB)){
23                 return true;
24             }
25         }
26         return false;
27     }
28 
29     //把字符串先变成一个字符数组，然后调整字符数组里面数据，最后把字符数组变成字符串
30     public static String rotate(String str){
31         //将字符串变成字符数组的方法 "ABC" ->['A''B''C'] ['B''C''A']
32         char[] arr = str.toCharArray();
33         //拿到零索引上的字符
34         char first = arr[0];
35         //剩余字符依次往前挪
36         for (int i = 1; i < arr.length; i++) {
37             arr[i-1] = arr[i];
38         }
39         //0索引放在最后
40         arr[arr.length-1] = first;
41         //利用字符数组创建一个字符串对象
42         String result = new String(arr);
43         return  result;
44     }
45 }