String Matching in an Array
Given an array of string words, return all strings in words that is a substring of another word. You can return the answer in any order.
A substring is a contiguous sequence of characters within a string
Example 1:
Input: words = ["mass","as","hero","superhero"]
Output: ["as","hero"]
Explanation: "as" is substring of "mass" and "hero" is substring of "superhero".
["hero","as"] is also a valid answer.
Example 2:
Input: words = ["leetcode","et","code"]
Output: ["et","code"]
Explanation: "et", "code" are substring of "leetcode".
Example 3:
Input: words = ["blue","green","bu"]
Output: []
Explanation: No string of words is substring of another string.
Constraints:
1 <= words.length <= 100
1 <= words[i].length <= 30
words[i] contains only lowercase English letters.
All the strings of words are unique.
思路一:嵌套遍历
public static List<String> stringMatching(String[] words) {
List<String> result = new ArrayList<>();
for (int i = 0; i < words.length; i++) {
for (int j = 0; j < words.length; j++) {
if (i == j) {
continue;
}
if (words[j].contains(words[i])) {
result.add(words[i]);
break;
}
}
}
return result;
}
标签:code,hero,easy,substring,1408,words,leetcode,string
From: https://www.cnblogs.com/iyiluo/p/17205770.html