1、根据名称注入
@Resource(name = "userService")
private UserService userService;
@Service("userService")
public class UserServiceImpl implements UserService
2、不指定名称，根据属性名进行注入
@Resource
private UserService userService;
@Service("userService")
public class UserServiceImpl implements UserService
3、根据类型进行注入
@Resource
private UserService userService;
@Service public class UserServiceImpl implements UserService
标签：implements,UserServiceImpl,Resource,Service,userService,UserService,注入 From： https://www.cnblogs.com/jixian/p/17157460.html