题目
约束
题解
解法一
class Solution {
public:
int uniquePaths(int m, int n) {
vector<vector<int>> f(m, vector<int>(n));
for (int i = 0; i < m; ++i) {
f[i][0] = 1;
}
for (int j = 0; j < n; ++j) {
f[0][j] = 1;
}
for (int i = 1; i < m; ++i) {
for (int j = 1; j < n; ++j) {
f[i][j] = f[i - 1][j] + f[i][j - 1];
}
}
return f[m - 1][n - 1];
}
};
解法二
class Solution {
public:
int uniquePaths(int m, int n) {
long long ans = 1;
for (int x = n, y = 1; y < m; ++x, ++y) {
ans = ans * x / y;
}
return ans;
}
};
标签:uniquePaths,int,路径,Solution,class,++,62,ans,LeetCode
From: https://www.cnblogs.com/chuixulvcao/p/17153647.html