HDOJ2115 I Love This Game

I Love This Game

Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 8290    Accepted Submission(s): 2864

Problem Description

Do you like playing basketball ? If you are , you may know the NBA Skills Challenge . It is the content of the basketball skills . It include several parts , such as passing , shooting , and so on. After completion of the content , the player who takes the shortest time will be the winner . Now give you their names and the time of finishing the competition , your task is to give out the rank of them ; please output their name and the rank, if they have the same time , the rank of them will be the same ,but you should output their names in lexicographic order.You may assume the names of the players are unique.

Is it a very simple problem for you? Please accept it in ten minutes.

Input

This problem contains multiple test cases! Ease test case contain a n(1<=n<=10) shows the number of players,then n lines will be given. Each line will contain the name of player and the time(mm:ss) of their finish.The end of the input will be indicated by an integer value of zero.

Output

The output format is shown as sample below.
Please output the rank of all players, the output format is shown as sample below;
Output a blank line between two cases.

Sample Input

10 Iverson 17:19 Bryant 07:03 Nash 09:33 Wade 07:03 Davies 11:13 Carter 14:28 Jordan 29:34 James 20:48 Parker 24:49 Kidd 26:46 0

Sample Output

Case #1 Bryant 1 Wade 1 Nash 3 Davies 4 Carter 5 Iverson 6 James 7 Parker 8 Kidd 9 Jordan 10

将时间转换为分（假设是 --时：分），然后排序（时间相同的按名字排）

import java.util.Scanner;

public class Main{
  private static Scanner scanner;
  private static int t[];
  private static String name[];

  public static void main(String[] args) {
    scanner = new Scanner(System.in);
    int cases = 1;// 计算次数
    boolean boo = false;
    while (scanner.hasNext()) {
      int n = scanner.nextInt();
      if (n == 0) {
        break;
      }

      name = new String[n];// 名字
      String time[] = new String[n];// 时间
      //接收数据
      for (int i = 0; i < n; i++) {
        name[i] = scanner.next();
        time[i] = scanner.next();
      }
      t = new int[n];// 时间
      // 计算时间
      // 全部转化为分
      for (int i = 0; i < n; i++) {
        String[] split = time[i].split(":");
        int h = Integer.parseInt(split[0]);
        int m = Integer.parseInt(split[1]);
        t[i] = h * 60 + m;
      }
      sort();// 进行排序
      /*for (int i = 0; i < time.length; i++) {
        System.out.println(t[i]);
      }*/
      if(boo){//不是第一个就先输出空行
        System.out.println();
      }
      System.out.println("Case #"+cases);
      int rank[] = new int[n];
      rank[0] = 1;//排名
      //先输出第一个
      System.out.println(name[0]+" "+rank[0]);
      for (int i = 1; i < n; i++) {
        if(t[i] == t[i-1]){
          rank[i] = rank[i-1];
        }else {
          rank[i] = i+1;
        }
        System.out.println(name[i]+" "+rank[i]);
      }
      
      cases++;
      boo = true;
    }
  }

  // 排序
  private static void sort() {
    for (int i = 0; i < name.length - 1; i++) {
      for (int j = i + 1; j < name.length; j++) {
        if (t[i] > t[j]) {// 时间从小到大
          swap(i, j);
        } else if (t[i] == t[j]) {
          if (name[i].compareTo(name[j]) > 0){
            swap(i, j);
          }
        }
      }
    }
  }

  // 交换
  private static void swap(int i, int j) {
    int temp = t[i];
    t[i] = t[j];
    t[j] = temp;

    String string = name[i];
    name[i] = name[j];
    name[j] = string;
  }
}