HDOJ1076 An Easy Task

An Easy Task

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 24613    Accepted Submission(s): 15866

Problem Description

Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him?

Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y.

Note: if year Y is a leap year, then the 1st leap year is year Y.

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains two positive integers Y and N(1<=N<=10000).

Output

For each test case, you should output the Nth leap year from year Y.

Sample Input

3 2005 25 1855 12 2004 10000

Sample Output

Hint

给出其实年份，求该年份的第N个闰年，计算闰年的方法都给了

import java.util.Scanner;

public class Main{
  private static Scanner scanner;
  public static void main(String[] args) {
    scanner = new Scanner(System.in);
    int cases = scanner.nextInt();
    while(cases-->0){
      int year = scanner.nextInt();
      int m = scanner.nextInt();
      int count = 0,i = 0;
      while(count<m){
        if(judgeYear(year+i)){
          count++;
        }
        i++;
      }
      System.out.println(year+i-1);
    }
  }
  private static boolean judgeYear(int i) {
    if((i%4==0 && i%100!=0 )|| i%400 == 0){
      return true;
    }
    return false;
  }
}