题目链接:https://www.luogu.com.cn/problem/P1387
- 二维前缀和模版题
#include<bits/stdc++.h>
using namespace std;
int n, m, a[105][105], s[105][105];
int ans;
int main()
{
cin>>n>>m;
for(int i=1; i<=n; i++)
for(int j=1; j<=m; j++)
cin>>a[i][j];//输入矩阵
for(int i=1; i<=n; i++)
for(int j=1; j<=m; j++)
s[i][j]=s[i-1][j]+s[i][j-1]-s[i-1][j-1]+a[i][j];//二维前缀和
for(int x1=1; x1<=n; x1++)
for(int y1=1; y1<=m; y1++)
for(int len=0; len+x1<=n && len+y1<=m; len++){//边长增量,len从0开始考虑1个点就是个正方形
int x2=x1+len;//右下点坐标位置
int y2=y1+len;
int mj=s[x2][y2]-s[x1-1][y2]-s[x2][y1-1]+s[x1-1][y1-1];//二维区间和
if(mj==(len+1)*(len+1))//判断是否为正方形
ans=max(ans, len+1);
}
cout<<ans;
return 0;
}
标签:www,cn,最大,int,P1387,正方形,105
From: https://www.cnblogs.com/tflsnoi/p/17135846.html