import java.util.concurrent.CompletableFuture;
import java.util.concurrent.ExecutionException;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
public class ThreadTest {
public static ExecutorService service = Executors.newFixedThreadPool(5);
public static void main(String[] args) throws ExecutionException, InterruptedException {
CompletableFuture<String> future01 = CompletableFuture.supplyAsync(() -> {
System.out.println("查询商品的信息");
return "商品";
}, service);
CompletableFuture<String> future02 = CompletableFuture.supplyAsync(() -> {
try {
Thread.sleep(3000);
System.out.println("查询属性");
} catch (InterruptedException e) {
throw new RuntimeException(e);
}
return "属性";
}, service);
CompletableFuture<String> future03 = CompletableFuture.supplyAsync(() -> {
System.out.println("查询图片信息");
return "图片";
}, service);
/**
* 等待全部运行完毕
* 第一种:阻塞式等待,这样会等待执行时间最长的线程 【不推荐】
*/
// future01.get();
// future02.get();
// future03.get();
/**
* 等待全部运行完毕
* 第二种:使用allof()方法等待所有线程运行完毕 【推荐】
*/
// CompletableFuture<Void> future = CompletableFuture.allOf(future01, future02, future03);
// future.get();//等待所有线程运行完毕
// ====================================================================
/**
* 等待其中一个运行完毕
*/
CompletableFuture<Object> anyOf = CompletableFuture.anyOf(future01, future02, future03);
anyOf.get();
System.out.println("运行结果::" + anyOf.get());
System.out.println("全部线程运行完毕");
}
public static void test(String[] args) throws ExecutionException, InterruptedException {
System.out.println("main-----start");
//thenRunAsync
CompletableFuture<Void> future = CompletableFuture.supplyAsync(() -> {
System.out.println("当前线程::" + Thread.currentThread().getId());
int i = 10/2;
System.out.println("运行结果::" + i);
return i;
}, service).thenRunAsync(()->{
System.out.println("任务二启动了");
},service);
//thenAcceptAsync
CompletableFuture<Void> voidCompletableFuture = CompletableFuture.supplyAsync(() -> {
System.out.println("当前线程::" + Thread.currentThread().getId());
int i = 10 / 2;
System.out.println("运行结果::" + i);
return i;
}, service).thenAcceptAsync((result) -> {
System.out.println("上一步的执行结果::" + result);
}, service);
//thenApplyAsync
CompletableFuture<String> stringCompletableFuture = CompletableFuture.supplyAsync(() -> {
System.out.println("当前线程::" + Thread.currentThread().getId());
int i = 10 / 2;
System.out.println("运行结果::" + i);
return i;
}, service).thenApplyAsync((result) -> {
return "hello---" + result;
}, service);
System.out.println(stringCompletableFuture.get());
CompletableFuture<Integer> future1 = CompletableFuture.supplyAsync(() -> {
System.out.println("任务一开始");
int i = 10 / 2;
System.out.println("任务一结束");
return i;
}, service);
CompletableFuture<Integer> future2 = CompletableFuture.supplyAsync(() -> {
System.out.println("任务二开始");
int i = 10 / 4;
System.out.println("任务二结束");
return i;
}, service);
//runAfterBoth:组合两个 future,不需要获取 future 的结果,只需两个 future 处理完任务后, 处理该任务。
// future1.runAfterBothAsync(future2, ()->{
// System.out.println("任务三开始");
// }, service);
//thenAcceptBoth:组合两个 future,获取两个 future 任务的返回结果,然后处理任务,没有 返回值
// future1.thenAcceptBothAsync(future2, (res1, res2)->{
// System.out.println("任务三开始");
// System.out.println("任务一的返回值::" + res1);
// System.out.println("任务二的返回值::" + res2);
// System.out.println("任务三结束");
// }, service);
//thenCombine:组合两个 future,获取两个 future 的返回结果,并返回当前任务的返回值
CompletableFuture<String> future3 = future1.thenCombineAsync(future2, (res1, res2) -> {
return res1 + "---" + res2 + "---" + "hello";
}, service);
System.out.println(future3.get());
System.out.println("main-----end");
}
}
标签:return,service,System,---,CompletableFuture,70,println,out
From: https://www.cnblogs.com/morehair/p/17099530.html