给你一个由不同字符组成的字符串 allowed 和一个字符串数组 words 。如果一个字符串的每一个字符都在 allowed 中，就称这个字符串是 一致字符串 。
请你返回 words 数组中 一致字符串 的数目。
输入：allowed = "cad", words = ["cc","acd","b","ba","bac","bad","ac","d"] 输出：4 解释：字符串 "cc"，"acd"，"ac" 和 "d" 是一致字符串。
class Solution(object):
def countConsistentStrings(self, allowed, words):
"""
:type allowed: str
:type words: List[str]
:rtype: int
"""
flag=1
n=0
for word in words:
flag=1
for char in word:
if char not in allowed:
flag=0
if(flag==1):
n=n+1
return n
标签：ac,cc,flag,1684,words,allowed,字符串 From： https://www.cnblogs.com/LYoungH/p/17084281.html