Web Navigation
Time Limit: 1000MS | Memory Limit: 10000K | |
Total Submissions: 41995 | Accepted: 18687 |
Description
Standard web browsers contain features to move backward and forward among the pages recently visited. One way to implement these features is to use two stacks to keep track of the pages that can be reached by moving backward and forward. In this problem, you are asked to implement this.The following commands need to be supported:
BACK: Push the current page on the top of the forward stack. Pop the page from the top of the backward stack, making it the new current page. If the backward stack is empty, the command is ignored.
FORWARD: Push the current page on the top of the backward stack. Pop the page from the top of the forward stack, making it the new current page. If the forward stack is empty, the command is ignored.
VISIT : Push the current page on the top of the backward stack, and make the URL specified the new current page. The forward stack is emptied.
QUIT: Quit the browser.
Assume that the browser initially loads the web page at the URL http://www.acm.org/
Input
Input is a sequence of commands. The command keywords BACK, FORWARD, VISIT, and QUIT are all in uppercase. URLs have no whitespace and have at most 70 characters. You may assume that no problem instance requires more than 100 elements in each stack at any time. The end of input is indicated by the QUIT command.Output
For each command other than QUIT, print the URL of the current page after the command is executed if the command is not ignored. Otherwise, print "Ignored". The output for each command should be printed on its own line. No output is produced for the QUIT command.Sample Input
VISIT http://acm.ashland.edu/
VISIT http://acm.baylor.edu/acmicpc/
BACK
BACK
BACK
FORWARD
VISIT http://www.ibm.com/
BACK
BACK
FORWARD
FORWARD
FORWARD
QUIT
Sample Output
http://acm.ashland.edu/
http://acm.baylor.edu/acmicpc/
http://acm.ashland.edu/
http://www.acm.org/
Ignored
http://acm.ashland.edu/
http://www.ibm.com/
http://acm.ashland.edu/
http://www.acm.org/
http://acm.ashland.edu/
http://www.ibm.com/
Ignored
#include<iostream>
#include<string>
#include<stack>
using namespace std;
//POJ1028
//实现网页浏览网站的访问手段
int main(){
string web="http://www.acm.org/";
string instructor;
stack <string> s,a;
string temp;
s.push(web);
while(cin>>instructor){
if(instructor=="QUIT"){
return 0;
}
if(instructor=="VISIT"){
while(!a.empty()){
a.pop();
}
cin>>web;
s.push(web);
cout<<web<<endl;
}
if(instructor=="BACK"){
if(!s.empty()){
a.push(s.top());
s.pop();
if(!s.empty()){
cout<<s.top()<<endl;
}
else{
cout<<"Ignored"<<endl;
//请回当前页面
s.push(a.top());
a.pop();
}
}
}
//若是模仿现在的网页浏览,在visit一个新的网页之后,是没有前进项的,保证的是一种单进程
//但若是stack a一直存在,则相当于visit功能是在原有进程中插入进程,并且插入进程拥有前进项
//因此在visit中,每次visit都会使得a栈清零则贴近日常使用
//forward只能是相对于backword而言的
if(instructor=="FORWARD"){
if(!a.empty()){
s.push(a.top());
a.pop();
cout<<s.top()<<endl;
}
else{
cout<<"Ignored"<<endl;
}
}
}
}
标签:POJ1028,http,acm,stack,command,edu,page From: https://www.cnblogs.com/walter-mitty/p/17072474.html