一、OKHttpUtil 功能
- 根据URL自动判断是请求HTTP还是HTTPS,不需要单独写多余的代码。
- 默认情况下Cookie自动记录,比如可以实现模拟登录,即第一次访问登录URL后后续请求就是登录状态。
- 自动识别304跳转并二次请求
- 支持代理配置
- 支持referer配置
- 支持User-Agent配置
- 自动识别并解压Gzip格式返回内容
- 支持springboot 配置文件
- 极简的封装调用
二、OKHttpUtil使用
1、 maven引入
<dependency> <groupId>io.github.admin4j</groupId> <artifactId>http</artifactId> <version>0.4.0</version> </dependency>
2、GET请求
最简单的使用莫过于用HttpUtil工具类快速请求某个接口:
Response response = HttpUtil.get("https://github.com/search", Pair.of("q", "okhttp")); System.out.println("response = " + response);
3、POST请求
一行代码即可搞定,当然Post请求也很简单:
# JSON 格式的body Response post = HttpUtil.post("https://oapi.dingtalk.com/robot/send?access_token=27f5954ab60ea8b2e431ae9101b1289c138e85aa6eb6e3940c35ee13ff8b6335", "{\"msgtype\": \"text\",\"text\": {\"content\":\"【反馈提醒】我就是我, 是不一样的烟火\"}}"); System.out.println("post = " + post); # form 请求 Map<String, Object> formParams = new HashMap<>(16); formParams.put("username", "admin"); formParams.put("password", "admin123"); Response response = HttpUtil.postForm("http://192.168.1.13:9100/auth/login", formParams ); System.out.println("response = " + response);
返回格式为JSON的 可以使用 HttpJsonUtil
自动返回JsonObject
JSONObject object=HttpJsonUtil.get("https://github.com/search", Pair.of("q","http"), Pair.of("username","agonie201218")); System.out.println("object = "+object);
4、文件上传
File file=new File("C:\\Users\\andanyang\\Downloads\\Sql.txt"); Map<String, Object> formParams=new HashMap<>(); formParams.put("key","test"); formParams.put("file",file); formParams.put("token","WXyUseb-D4sCum-EvTIDYL-mEehwDtrSBg-Zca7t:qgOcR2gUoKmxt-VnsNb657Oatzo=:eyJzY29wZSI6InpoYW56aGkiLCJkZWFkbGluZSI6MTY2NTMwNzUxNH0="); Response response=HttpUtil.upload("https://upload.qiniup.com/",formParams); System.out.println(response);
5、下载文件
HttpUtil.down("https://gitee.com/admin4j/common-http","path/");
6、HttpRequest 链式请求
# get Response response=HttpRequest.get("https://search.gitee.com/?skin=rec&type=repository") .queryMap("q","admin4j") .header(HttpHeaderKey.USER_AGENT,"admin4j") .execute(); System.out.println("response = "+response); # post form Response response=HttpRequest.get("http://192.168.1.13:9100/auth/login") .queryMap("q","admin4j") .header(HttpHeaderKey.USER_AGENT,"admin4j") .form("username","admin") .form("password","admin123") .execute(); System.out.println("response = "+response);
标签:OKHttpUtil,搞定,Http,请求,System,formParams,println,response,out From: https://www.cnblogs.com/xfbk/p/17050980.html