C语言例题
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题目:一个整数，它加上100后是一个完全平方数，再加上168又是一个完全平方数，请问该数是多少?
#include <stdio.h> #include <math.h> int main() { int x,i,y; for (int i = 0; i < 100000; ++i) { x=sqrt(i+100); y=sqrt(i+268); if (pow(x,2)==i+100&&pow(y,2)==i+268){ printf("%d\n",i); } } return 0; }
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题目:企业发放的奖金根据利润提成。
- 利润(工)低于或等于10万元时，奖金可提10%;
- 利润高于10万元，低于20万元时，低于10万元的部分按10%提成，高于10万元的部分，可提成7.5%;
- 20万到40万之间时，高于20万元的部分，可提成5%;#40万到60万之间时高于40万元的部分，可提成3%;
- 60万到100万之间时，高于60万元的部分，可提成1.5%;#高于100万元时，超过100万元的部分按1%提成。
从键盘输入当月利润I，求应发放奖金总数?
#include <stdio.h> int main() { int bonus; float profit; printf("Please input the proft:"); scanf("%f",&profit); if(profit<=100000){ bonus=0.1*profit;} else if(profit>100000&&profit<200000){ bonus=(profit-100000)*0.075+10000; } else if(profit>=200000&&profit<400000){ bonus=(profit-200000)*0.05+10000+100000*0.075; } else if(profit>=400000&&profit<600000){ bonus=(profit-400000)*0.03+200000*0.05+10000+100000*0.075; } else if(profit>=600000&&profit<=1000000){ bonus=(profit-600000)*0.015+200000*0.05+10000+100000*0.075+200000*0.03; } else if(profit>1000000){ bonus=(profit-1000000)*0.01+200000*0.05+10000+100000*0.075+200000*0.03+400000*0.015; } printf("bonus=%d",bonus); return 0; }
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题目:有1、2、3、4个数字，能组成多少个互不相同且无重复数字的三位数?都是多少?
#include <stdio.h> int main() { int i,j,k; int s=0; for (int i = 1; i <5 ; i++) { for (int j = 1; j <5 ; j++) { for (int k = 1; k <5 ; k++) { if(i!=j&&i!=k&&k!=j){ s++; printf("%d%d%d\n",i,j,k); } } } } printf("%d",s); return 0; }
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题目:输入某年某月某日，判断这一天是这一年的第几天?
#include <stdio.h> int main() { int year,month,day,a,s; printf("Please input the year month and day:"); scanf("%d,%d,%d",&year,&month,&day); if(year%4==0&&year%100!=0){ switch (month){ case 1:{printf("Today is the %d day",day); }break; case 2:{printf("Today is the %d day",day+31); }break; case 3:{printf("Today is the %d day.",day+31+29); }break; case 4:{printf("Today is the %d day.",day+31+29+31); }break; case 5:{printf("Today is the %d day.",day+31+29+31+30); }break; case 6:{printf("Today is the %d day.",day+31+29+31+30+31); }break; case 7:{printf("Today is the %d day.",day+31+29+31+30+31+30); }break; case 8:{printf("Today is the %d day.",day+31+29+31+30+31+30+31); }break; case 9:{printf("Today is the %d day.",day+31+29+31+30+31+30+31+31); }break; case 10:{printf("Today is the %d day.",day+31+29+31+30+31+30+31+31+30); }break; case 11:{printf("Today is the %d day.",day+31+29+31+30+31+30+31+31+30+31); }break; case 12:{printf("Today is the %d day.",day+31+29+31+30+31+30+31+31+30+31+30); }break; } } else{ switch (month){ case 1:{printf("Today is the %d day",day); }break; case 2:{printf("Today is the %d day",day+31); }break; case 3:{printf("Today is the %d day.",day+31+28); }break; case 4:{printf("Today is the %d day.",day+31+29+31); }break; case 5:{printf("Today is the %d day.",day+31+29+31+30); }break; case 6:{printf("Today is the %d day.",day+31+29+31+30+31); }break; case 7:{printf("Today is the %d day.",day+31+29+31+30+31+30); }break; case 8:{printf("Today is the %d day.",day+31+29+31+30+31+30+31); }break; case 9:{printf("Today is the %d day.",day+31+29+31+30+31+30+31+31); }break; case 10:{printf("Today is the %d day.",day+31+29+31+30+31+30+31+31+30); }break; case 11:{printf("Today is the %d day.",day+31+29+31+30+31+30+31+31+30+31); }break; case 12:{printf("Today is the %d day.",day+31+29+31+30+31+30+31+31+30+31+30); }break; } } return 0; }今天又是废话文学的一天...T-T
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题目:输入三个整数x, y,z，请把这三个数由小到大输出。
#include <stdio.h> int main() { int x,y,z; printf("Please input three numbers:"); scanf("%d,%d,%d",&x,&y,&z); if(x<=y&&x<=z){ if(y<=z){ printf("%d,%d,%d",x,y,z); } else{ printf("%d,%d,%d",x,z,y); } } if(y<=x&&y<=z){ if(x<=z){ printf("%d,%d,%d",y,x,z); } else{ printf("%d,%d,%d",y,z,x); } } if(z<=x&&z<=y){ if(x<=y){ printf("%d,%d,%d",z,x,y); } else{ printf("%d,%d,%d",z,y,x); } } return 0; }
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题目:用*号输出字母C的图案。
#include <stdio.h> int main() { printf("*********\n"); printf("*\n"); printf("*\n"); printf("*\n"); printf("*\n"); printf("*********"); return 0; }
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题目:输出9+9口诀。
#include <stdio.h> int main() { int i,j; for (int i = 1; i < 10; i++) { for (int j = 1; j <=i ; j++) { printf("%d*%d=%d ",j,i,i*j); } printf("\n"); } return 0; }
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题目:古典问题（兔子生惠)∶有一对兔子，从出生后第3个月起每个月都生一对兔子，小兔子长到第三个月后每个月又生一对兔子，假如兔子都不死，问每个月的兔子总数为多少?(输出前40个月即可)
#include <stdio.h> int Fib(int n){ if(n<=2){ return 1; } else{ return Fib(n-1)+Fib(n-2); } } int main() { int n,i; printf("Please input a number:"); scanf("%d",&n); for (int i = 1; i<=n; i++) { printf("%d\n",Fib(i)*2); } return 0; }
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题目:判断101到200之间的素数。
#include <stdio.h> int main() { int i,j; for (int i = 101; i <200 ; i++) { for (int j = 2; j <i ; j++) { if (i%j==0){ break; } if(j>=i/2){ printf("%d\n",i); break; } } } return 0; }当结果出现多个重复值时可在循环后加入break;
- 题目:打印出所有的"水仙花数"，所谓"水仙花数"是指一个三位数，其各位数字立方和等于该数本身。例如:153是一个"水仙花数"，因为153=1的三次方+5的三次方+3的三次方。
#include <stdio.h>
#include <math.h>
int main() {
int i,j,k;
for (int i = 100; i < 1000; i++) {
j=i/10;
if ((pow(i/100,3)+pow(j%10,3)+pow(i%10,3))==i){
printf("%d\n",i);
}
}
return 0;
}
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题目:将一个正整数分解质因数。例如:输入90,打印出90=233*5。
#include <stdio.h> int main() { int i,x; printf("Please input a number:"); scanf("%d",&x); printf("%d=",x); for (int i =2; i <=x ; i++) { while (x%i==0){ printf("%d",i); x=x/i; if(x!=1){ printf("*"); } } } return 0; }
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题目:利用条件运算符的嵌套来完成此题:学习成绩>=90分的同学用A表示，60-89分之间的用B表示，60分以下的用C表示.
#include <stdio.h> int main() { int score; printf("Please input the score:"); scanf("%d",&score); if (score>=90){ printf("A"); } else{ (score<60)?printf("C"):printf("B"); } return 0; }
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题目:输入两个正整数m和n，求其最大公约数和最小公倍数。
#include <stdio.h> int main() { int m,n,i,j; int s=1; printf("Please input m and n:"); scanf("%d,%d",&m,&n); //最大公约数：共有质因数的乘积 //最小公倍数：两个数的乘积/最大公约数 for (int i = 2; i <=m ; i++) { for (int j = 2; j <=n ; j++) { if ((m%i==0)&&(n%j==0)){ while (i==j){ s=s*i; break; //如果不加则一直在while里循环 } } } } printf("the greatest common divisor is %d\n",s); printf("the least common multiple is %d",m*n/s); return 0; }
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题目:输入一行字符，分列统计出其中英文字母、空格、数字和其它字符的个数。
#include <stdio.h> #include <string.h> #include <ctype.h> int main() { int i; int s1=0; int s2=0; int s3=0; int s4=0; char a[100]; printf("Please input chars:"); gets(a); for (int i = 0; i <strlen(a) ; i++) { if (isalpha(a[i])){ s1++; } else if(a[i]==' '){ s2++; } else if(isdigit(a[i])){ s3++; } else{ s4++; } } printf("the alpha has %d\n",s1); printf("the blanket has %d\n",s2); printf("the number has %d\n",s3); printf("the other has %d",s4); return 0; }
- 题目:求s=a+aa+aaa+aaaa+aa. ..a的值，其中a是一个数字。例如2+22+222+2222+22222(此时共有5个数相加)，几个数相加有键盘控制。
#include <stdio.h>
#include <math.h>
int main() {
int n,i,a;
int sum=0;
printf("Please input a number:");
scanf("%d",&n);
for (int i = 1; i <=n ; i++) {
a+=pow(10,(i-1))*2;
sum+=a;
}
printf("%d",sum);
return 0;
}
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题目:一个数如果恰好等于它的因子之和,这个数就称为"完数"。例如6李1+2+3.编程找出10日日以内的所有完数。
#include <stdio.h> int main() { int i, j, sum; for (i = 1; i <= 1000; i++) { //或者i,j都从2开始sum从1开始 sum = 0; //必须在for循环中赋值，如果在for循环外面赋值则每次外循环开始都变成0 //每一个i对应一个sum值因此需要在i循环内重新让sum=0 for (j = 1; j <= i / 2; j++) { if (i % j == 0) sum += j; } if (sum == i) { printf("%d \n", i); } } return 0; }
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题目:一球从100米高度自由落下，每次落地后反跳回原高度的一半;再落下.求它在第10次落地时,共经过多少米?第10次反弹多高?
#include <stdio.h> int main() { float h=100; int n,i; float sum=100; for (int i = 1; i <=10 ; i++) { h = h / 2.0; sum += h; if(i==10){ printf("The tenth height is %f\n", h); } } printf("sum=%f", sum); return 0; }
标签：int,31,30,C语言,break,printf,例题,day From： https://www.cnblogs.com/yuanyu610/p/17048196.html