题目要求
实现 TS 内置的 Pick<T, K>，但不可以使用它。
从类型 T 中选择出属性 K，构造成一个新的类型。
例如：
interface Todo {
title: string
description: string
completed: boolean
}
type TodoPreview = MyPick<Todo, 'title' | 'completed'>
const todo: TodoPreview = {
title: 'Clean room',
completed: false,
}
English - Subject
Implement the built-in Pick<T, K> generic without using it.
Constructs a type by picking the set of properties K from T
For example:
interface Todo {
title: string
description: string
completed: boolean
}
type TodoPreview = MyPick<Todo, 'title' | 'completed'>
const todo: TodoPreview = {
title: 'Clean room',
completed: false,
}
答案
type MyPick<T extends {}, K extends keyof T> = { [P in K]: T[P] };